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Use the JavaScript function JSON.stringify () to convert it into a string. const myJSON = JSON.stringify(obj); The result will be a string following the JSON notation. myJSON is now a string, and ready to be sent to a server: Example. const obj = {name: "John", age: 30, city: "New York"}; const myJSON = JSON.stringify(obj);. This tool transforms the input JSON string to a valid JavaScript value or expression. It uses your browser's parse method, which parses a string according to JSON grammar (syntax) rules. If the string doesn't have syntax errors, it creates a simple JavaScript value or a more complex object from the string. You can try using regex to remove quotes from your string. var strWithOutQuotes= strWithQuotes.replace(/['"]+/g, '') ['"] is a character class, matches both single and double quotes. you can replace this with "to only match double quotes. +: one or more quotes, chars, as defined by the preceding char-class (optional).
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JSON stands for JavaScript Object Notation and has become the most popular format for transfer and storage of data since due to its light weight nature A string is a sequence of zero or more Unicode characters, wrapped in double quotes, using backslash escapes A string is a sequence of zero or more Unicode characters, wrapped in double quotes. Backslash in this case is an escape character for quotes. Json format requires key values to be within quotes. If we want to store json string in c# we cannot do this: string jsonString = "{ "name" : "John" }"; For the language to store this json object as actual string we need to write. string jsonString = "{ \"name\": \"John\" }";. Assuming that we have a JSON key whose value is "my\id", which includes a backslash. In order to store this in JSON data, we will need two backslashes, as below: {"my\\id": "value"} The extra backslash is needed because it is a special escape character that JSON parser will try to evaluate and \i will become invalid. Replace all backslashes with empty string using gsub: json.gsub('\\', '') Note that the default output in a REPL uses inspect, which will double-quote the string and still include backslashes to escape the double-quotes. Use puts to see the string's exact contents:. Your string is invalid, but assuming it was valid, you'd have to do: var finalData = str.replace (/\\/g, ""); When you want to replace all the occurences with .replace, the first parameter must be a regex, if you supply a string, only the first occurrence will be replaced, that's why your replace wouldn't work. Cheers Share.
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Also, the backslash characters are not really in the JSON file. Solution 7 if you use Copy Code JsonConvert.SerializeObject in your code it will add backslash by default, and you can remove it by playing it with string. But, its better to create a class file and return it directly. Strictly, in case of webapi Posted 31-Jul-19 0:44am futurevj. Search: Json Backslash Problem Python. Here structured data is the JSON --- Looping over the lines: In Python you can store as much information as you want Python map() The map() function applies a given function to each item of an iterable (list, tuple etc 6+) Admin Go SDK — Go 1 It is an inclusive introduction to Computer Science that takes the pedagogical approach of the right tool for. 2021. 11. 10. · Note that the regex just looks for one backslash; there are two in the literal because you have to escape backslashes in regular expression literals with a backslash (just like in a string literal). The g at the end of the regex tells replace to work throughout the string ("global"); otherwise, it would replace only the first match. Within a string "\\" represents a single backslash. Therefore the actual value of your declared string json is "C:\test\sample.txt". To replace a double backslash with a single backslash you should use json.Replace(@"\\", @"\") Here the @ symbol instructs the runtime not to escape any characters within the string. Best Regards, Maher.
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The simplest and smallest library in our review is JSON-java also known as org.json. To construct a JSON object, we simply create an instance of JSONObject and basically treat it like a Map: JSONObject jsonObject = new JSONObject(); jsonObject.put("message", "Hello \"World\""); String payload = jsonObject.toString();. Since PHP 5.4 there are constants which can be used by json_encode () to format the json reponse how you want. To remove backslashes use: JSON_UNESCAPED_SLASHES. Like so: View the PHP documentation for more constants and further information: However you have to be extremely careful here because you need to make sure that all your values have.
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